2(4x^2+4x-2)=8x^2+8x-2

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Solution for 2(4x^2+4x-2)=8x^2+8x-2 equation:


Simplifying
2(4x2 + 4x + -2) = 8x2 + 8x + -2

Reorder the terms:
2(-2 + 4x + 4x2) = 8x2 + 8x + -2
(-2 * 2 + 4x * 2 + 4x2 * 2) = 8x2 + 8x + -2
(-4 + 8x + 8x2) = 8x2 + 8x + -2

Reorder the terms:
-4 + 8x + 8x2 = -2 + 8x + 8x2

Add '-8x' to each side of the equation.
-4 + 8x + -8x + 8x2 = -2 + 8x + -8x + 8x2

Combine like terms: 8x + -8x = 0
-4 + 0 + 8x2 = -2 + 8x + -8x + 8x2
-4 + 8x2 = -2 + 8x + -8x + 8x2

Combine like terms: 8x + -8x = 0
-4 + 8x2 = -2 + 0 + 8x2
-4 + 8x2 = -2 + 8x2

Add '-8x2' to each side of the equation.
-4 + 8x2 + -8x2 = -2 + 8x2 + -8x2

Combine like terms: 8x2 + -8x2 = 0
-4 + 0 = -2 + 8x2 + -8x2
-4 = -2 + 8x2 + -8x2

Combine like terms: 8x2 + -8x2 = 0
-4 = -2 + 0
-4 = -2

Solving
-4 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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